Nadirah H.

asked • 02/13/19

Math question help pls

The White (Chalk) Cliffs of Dover are approximately 120 meters (m) thick. They are composed of biogenic sediment once on an abyssal plain.


If these sediments accumulate at rates of 0.2mm/year how long did they take to accumulate.

Useful info: 1m = 100cm 1cm = 10mm



Gerald E.

1m = 100 cm = 1000 mm 120 m thick cliffs in mm = 120 m x 1000 mm/m = 120,000 mm. Accumulation rate is 0.2 mm/yr. Accumulation time = thickness in mm divided by accumulation rate in mm per year. 120,000 mm / 0.2mm/yr --> 600,000 years.
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04/28/20

Gerald E.

1m = 100 cm = 1000mm 120 m cliffs = 120 m x 1000 mm/m = 120,000 mm. Time required for accumulation = thickness (120,000mm) / annual accumulation rate ( 0.2 mm/yr) = 120,000/0.2 = 600,000 years.
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04/28/20

1 Expert Answer

By:

Krystin R. answered • 12/02/20

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Krystin- Geologist, Geochemist, and Mathematician

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First you must convert the height of the White Cliffs of Dover from meters to millimeters:

1 meter (m) = 1000 millimeters(mm); thus 120 m = 120,000 mm


Then by dividing the height in millimeters (120,000) by the accumulation rate in millimeters/year (0.2mm/yr), you are left with the number of years required:


120,000 mm ÷ (0.2mm/year) = 600,000 years

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