g'(x) = (2/3)x-1/3
g'(a) = (2/3)a-1/3
You might need to remember what an exponent of -1/3 means.
Nancy A.
asked • 02/12/19Calculus 1 chapter 2
g(x) = x2/3
(a) If a ≠ 0, find g'(a)
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