A=(1/x^2)(x-3)
A' = (6/x^3)-(1/x^2)
x=6
Gennaro C.
asked • 02/07/19AP CALCULUS mutiple choice question
the point (3,0), (x,(1/x^2) and (3, (1/x^2)) are vertices of a rectangle, where x is greater than or equal to 3. For what value of x does the rectangle have a maximum area?
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