Not quite!
π√x[1+(1/4)√y]
Not quite!
π√x[1+(1/4)√y]
π√x + (1/4)π√x√y
Almost. When you factor out the π√x, you leave a 1 behind, not a zero.
π√x(1 + (1/4)√y)
One way to check is to multiply the factored form out and see if you end up with the starting expression
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