Stella L. answered 10/30/14
Tutor
New to Wyzant
For part (a), we are told that 19 students liked exactly two fruits so, we
Let x equal to the number of students who liked apples and bananas ONLY
Let y equal to the number of students who liked bananas and strawberries ONLY
Let z equal to the number of students who liked apples and strawberries ONLY
that way, the equation would be:
x + y + z = 19
Now we let c equal to the number of students who liked all three fruits
Given that
- 11 liked apples and bananas means...
x + c = 11
- 15 liked bananas and strawberries means...
y + c = 15
- 17 liked apples and strawberries means...
z + c = 17
- 11 liked apples and bananas means...
x + c = 11
- 15 liked bananas and strawberries means...
y + c = 15
- 17 liked apples and strawberries means...
z + c = 17
Now solve for x, y, z
x = 11 - c
y = 15 - c
z = 17 - c
Then, substitute it in the first equation and solve for c
x + y + z = 19
(11 - c) + (15 - c) + (17 - c) = 19
-3c = 19 - 11 - 15 - 17
c = -24/-3
c = 8
So the number of students who liked all three fruits is 8
With that answer, we can now solve for part (b)
Let a equal to the number of students who liked apples ONLY
Given that
- 34 liked apples means...
a + x + z + c = 34
Now we know that
c = 8
x = 11 - c = 3
z = 17 - c = 9
z = 17 - c = 9
So we substitute it into our equation and solve for a
a + x + z + c = 34
a + 3 + 9 + 8 = 34
a = 14
So the number of students who liked apples only is 14