find work done in increasing velocity of a body of mass 10 kg from 5m/s to 15m/s'.

Answer 1

The amount of work required is equal to the change in kinetic energy (KE). Beginning KE = 0.5mv² =(0.5)(10)(5)² = 125 J. Ending KE = (0.5)(10)(15)² = 1,125 J. Therefore, the work required is 1125 - 125 = 1000 J.