
Byron S. answered 10/29/14
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Math and Science Tutor with an Engineering Background
Rolle's Theorem states that if a function is continuous and differentiable over an interval [a,b] and f(a) = f(b) then somewhere in the interval there must be a "flat" point at x=c, where f'(c) = 0.
f(x) = 1 - x2/3
This is a polynomial, so it is continuous and differentiable everywhere.
f(-1) = 1 - (-1)2/3 = 1 - 1/3 = 2/3
f(1) = 1 - 12/3 = 1 - 1/3 = 2/3
This function satisfies the conditions of Rolle's Theorem.
f'(x) = -2/3 x
f'(c) = -2/3 c = 0
c = 0
c = 0 ∈ [-1,-1] satisfies Rolle's Theorem.
Dhruv P.
Can you also help me with this one
10/29/14