If f(x) = x^3+x , and a = 10 find (f^-1)'(a) =

Answer 1

When x = 2, x^3 + x = 10. f'(x) = 3x^2 + 1, so f'(2) = 3*2^2 + 1 = 3*4_1 = 13.

Therefore (f^-1)'(10 ) = 1/(f'(2) = 1/13