Tom K. answered 12/30/18
Knowledgeable and Friendly Math and Statistics Tutor
There are 15 in set B and 150 not in B. We select 15 of 15 in B and 112 of 150 not in B. This is the hypergeometic distribution.
C(15,15)C(150,112)/C(165,112) = C(150,112)/C(165,112) = C(150,38)/C(165,38) = P(150,38)/P(165,38) = P(127,15)/P(165,15) is approximately .0161
Narma S.
But would this still apply if you are making a selection 1 by 1 (1-127 would have a different sized pool since pulling one card would decrease the overall pool by 1 of that card). Thanks for the answer, by the way!12/30/18