What is an equation of the line that passes through (3, -8) and has slope -2?

Answer 1

we know a point (3, -8) and the slope m = -2

from there i would plug into the point-slope form and simplify it down into slope-intercept

y - (-8) = -2(x - 3)

y + 8 = -2x + 6

y = -2x - 2

Answer 2

Hi Mernique,

We can find the equation of a line using the Point-Slope formula when we have a point and a slope.

Recall that the Point-Slope formula is:

Y - Y₁ = m(X - X₁)

Also remember that you plug in for Y₁ and X₁ from your point and slope for M.

So we have:

Point = (3, -8) therefore our X₁ = 3 and Y₁ = -8

Slope = m = -2

y - (-8) = -2(x - 3) **Be careful of the y - (-8) which becomes y+8

y + 8 = -2x + 6 **distribute the -2

-8 -8 **subtract 8 from both sides to move it over.

y = -2x - 2 ANSWER