Tim T. answered 04/01/19
Math: K-12th grade to Advanced Calc, Ring Theory, Cryptography
Greetings! Lets solve this problem shall we?!
Lets begin by noticing that we do not have the region to find the area so we must find the x values where this area is located. So, instead of graphing it on the calculator, we can find these x-values by setting the two equations equal to each other such that
2x+3 = -x2+10x-3
x2+2x+3 = 10x - 9
x2-8x+3 = -9
x2-8x-12 = 0
(x-6)(x-2) = 0
So x= 2 and 6 ...... These are our limits to integrate and find the area!
Then,
∫26 [(-x2+10x-9) - (2x+3)] dx = ∫62 (-x2+8x-12)dx = (-x3/3 + 4x2 - 12x)62 = 32/3
Hope this helped!