What is the vertical asymptote of f(x)= 2 / x^2 - 2x -3 ?

Answer 1

f(x) = 2/(x²-2x-3)

Factor the denominator:

f(x) = 2/(x-3)(x+1)

You can't divide by zero, so the values of x that make the denominator equal to zero will be vertical asymptotes: x = 3 and x = -1.