Melissa B.
asked • 12/05/18find y' if y=3(x^3-7x+2)^15+4x^2-2
There is one place of uncertainty in your question: in the exponent you have written 15+4x2-2. I am going to assume that you mean 13+4x2. Iff you meant something different, you will need to modify the answer accordingly.
y'(x) = 3(13+4x2)(8x)(x3-7x+2)(3x2-7)
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Melissa B.
it supposed to be (x^3-7x+2)^15 +4x^2-212/05/18