calculus help!!!

Question

find lim x to the right of 9 √x-3/x-9 and simplify

Answer 1

lim_x→9⁺ [(√x -3) / (x-9)] has the form 0/0

By L'Hopital's Rule, the given limit is equivalent to:

lim_x→9⁺[(1/ (2√x)) / 1] = 1/6