Good B.

asked • 11/26/18

Question: y=x^2 SIN (3x)

y=x2 sin(3x)


= 2x SIN (3x) + x^2 (3cos(3x)) ---> i'm confused how to get the 3 in front of cos

= 2x SIN (3x) +3x^2 cos (3x)

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