Raymond B. answered 05/04/24
Math, microeconomics or criminal justice
100A+150B </=600,000
2A +3B </= 12,000, (6,000, 0), (0,4,000)
A+B</=250 (250,0), (0,250)
max 30A+40B
graph 2nd & 3rd inequalities, A on vertical axis, B on horizontal. find the vertices of the enclosed area
(0,0), (250,0), (0,250)
40(250) - 150(40) = 4,000
30(250) -100(30) = $4,500 is maximum profit with 250 A and 0 B