
Patrick B. answered 11/12/18
Math and computer tutor/teacher
Area A = L*w = 32 ---> L = 32/w
Perimeter P = 2L + 2W
= 2 (32/w) + 2w
= 64/w + 2w
= (64 +2w^2)/w
0= dP/dw = {w ( 4w) - (64 +2w^2) }/w^2
0 = 4w^2 - 64 - 2w^2
0 = 2w^2 - 64
w^2 = 32
w = 4*Sqrt(2)
L = 32/(4*sqrt(2)) = 8/sqrt(2) = 8*sqrt(2)/2 = 4*Sqrt(2)
Max perimeter is 16*sqrt(2)