Inactive Tutor answered 11/12/18
A = L w
20 = 2L + 2w ---> 10 = L + w
----> L = 10 - w
A = (10-w)w
A(w) = (10-w)w , so area is a function of width w
= 10w - w^2
0 = dA/dw = 10 - 2w
10 = 2w
w = 5
Length and width are both 5
Erik K.
asked 11/12/18Find the dimensions of the rectangle of maximum area that can be formed from a 20-in.
piece of wire.
Inactive Tutor answered 11/12/18
A = L w
20 = 2L + 2w ---> 10 = L + w
----> L = 10 - w
A = (10-w)w
A(w) = (10-w)w , so area is a function of width w
= 10w - w^2
0 = dA/dw = 10 - 2w
10 = 2w
w = 5
Length and width are both 5
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