Mean Value Theorem:
(cos a - cos b)/(a -b) = -sin c for some value of c between a and b
|cos a - cos b| = |-sin c||a - b|
but since |-sin c| is less than of equal to 1,
|cos a - cos b| is less than or equal to |a - b|
Licia H.
asked 11/07/18Prove that the absolute value of cos(a)-cos(b) is less than or equal to the absolute value of a-b for all a and b
Mean Value Theorem:
(cos a - cos b)/(a -b) = -sin c for some value of c between a and b
|cos a - cos b| = |-sin c||a - b|
but since |-sin c| is less than of equal to 1,
|cos a - cos b| is less than or equal to |a - b|
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