Calculas help!!!

Question

 A spherical snowball is melting so that its diameter is decreasing at rate of 0.1 cm/min. At what is the rate is the volume of the snowball changing when the diameter is 11 cm?

The volume is changing at a rate of  (blank) cm^3/min

Answer 1

V = (4/3) pi r³

dV/dt = 4 pi r² dr/dt = 2 pi (d/2)² dd/dt

where V is Volume, r is radiusm and d is diameter.

Now just plug in the numbers in teh problem and do the calculation.