The probability that Joe makes a free throw is 0.85. What is the probability that he will miss the next two free throws he takes?

Answer 1

Hello Karina,

The probability of making a free throw,

P(making a free throw) = .85

→ P(NOT making a free throw) = .15 {Complementary events have to add up to 1}.

So the probability of missing the next two free throws is

(.15) * (.15) = .0225 = 2.25%.

Thank you for the question.

Michael E.