OK, you got the derivative; the value of the derivative at x = 3 is -1, the slope of the tangent.

The point on the curve at x = 3 is (3,2).

So you need the equation of the straight line with slope = =1 through (3,2),

Amber K.

asked • 10/30/18equation is 4/(x-1) i got the derivative as -4x/(x-1)^2

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OK, you got the derivative; the value of the derivative at x = 3 is -1, the slope of the tangent.

The point on the curve at x = 3 is (3,2).

So you need the equation of the straight line with slope = =1 through (3,2),

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