OK, you got the derivative; the value of the derivative at x = 3 is -1, the slope of the tangent.
The point on the curve at x = 3 is (3,2).
So you need the equation of the straight line with slope = =1 through (3,2),
Amber K.
asked 10/30/18equation is 4/(x-1) i got the derivative as -4x/(x-1)^2
OK, you got the derivative; the value of the derivative at x = 3 is -1, the slope of the tangent.
The point on the curve at x = 3 is (3,2).
So you need the equation of the straight line with slope = =1 through (3,2),
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.