y’ = 6x - 4
at x=2 y=-1
y’ = 6*2-4 = 8
y-(-1) = 8(x-2)
y+1 = 8x-16
y = 8x-17
Normal line would have a slope of -1/8
y + 1 = -1/8 * (x - 2)
y = (-1/8)x - 3/4
Justin G.
asked 10/29/18Use the equation y=3x^2 -4x-5 to answer the following questions.
a.) Write the equation of the tangent line drawn to this curve at x=2. Answer in general form.
b.) find the slope of the normal line drawn to this curve at x=2
y’ = 6x - 4
at x=2 y=-1
y’ = 6*2-4 = 8
y-(-1) = 8(x-2)
y+1 = 8x-16
y = 8x-17
Normal line would have a slope of -1/8
y + 1 = -1/8 * (x - 2)
y = (-1/8)x - 3/4
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