
Yefim S. answered 09/08/19
Tutor
5
(20)
Math Tutor with Experience
R = -4p^2 +4000p
max R we get for p = -4000/(2(-4)) = 500
max R = -4*500^2 + 4000*500 = $1000000
Megan H.
asked 10/28/18it’s asking to sketch the graph of the function, find what unit price should be established for the water heater to maximize revenue and what is the maximum revenue?
Yefim S. answered 09/08/19
Math Tutor with Experience
R = -4p^2 +4000p
max R we get for p = -4000/(2(-4)) = 500
max R = -4*500^2 + 4000*500 = $1000000
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