
Arturo O. answered 05/22/20
Experienced Physics Teacher for Physics Tutoring
a(t) = dv/dt = (-1/2)(3t-3/2) = (-3/2)t-3/2
x(t) = ∫v(t)dt = ∫3t-1/2dt = 3t1/2/(1/2) + c = 6t1/2 + c
x(1) = 11
11 = 6(1)1/2 + c
11 = 6 + c
c = 5
x(t) = 6t1/2 + 5
Lene C.
asked 10/27/18Consider a particle moving along the x-axis where x (t ) is the position of the particle at time t, x' (t ) is its velocity, and x'' (t ) is its acceleration.
A particle moves along the x-axis at a velocity of v ( t ) = 3/√t , t > 0. At time t = 1, its position is x = 11. Find the acceleration and position functions for the particle.
Arturo O. answered 05/22/20
Experienced Physics Teacher for Physics Tutoring
a(t) = dv/dt = (-1/2)(3t-3/2) = (-3/2)t-3/2
x(t) = ∫v(t)dt = ∫3t-1/2dt = 3t1/2/(1/2) + c = 6t1/2 + c
x(1) = 11
11 = 6(1)1/2 + c
11 = 6 + c
c = 5
x(t) = 6t1/2 + 5
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.