
Doug C. answered 10/23/18
Math Tutor with Reputation to make difficult concepts understandable
The function g contains point (2,6). The slope of the tangent line at that point is -4. So the equation of that tangent line is y-6=-4(x-2) -- point slope. Solving for y gives the "linearization" of g.
L(x) = -4x + 14
So, L(2.1) = -4(2.1) + 14 = 5.6.
For an upper bound on the error use the Linear Approximation Theorem where B=3.
That is the upper bound is B/2 (x-a)^2, or 1.5(2.1-2)^2. So, the approximation is:
5.6 +/- .015