Let y = 5 x 2 + 4 x + 3 . Find the differential d y when x = 4 and d x = 0.3

Question

confused need help

Answer 1

$y=5x^2+4x+3$

$dy=d(5x^2)+d(4x)+d(3)$

$dy=10xdx+4dx$

Plug in x = 4 and dx = 0.3 and compute the answer