
Mark M. answered 10/15/18
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
f(x) = x^3 - x
f'(x) = 3x^2 - 1
f'(-1) = 3(-1)^2 - 1
f'(-1) = 2
(y - 1) = 2(x + 1)
Rafael F.
asked 10/15/18Be "R" a straight that passing for (−1, 1) and is tangent to the graphic of f (x) = x^3−x. To determined "R".
Mark M. answered 10/15/18
Mathematics Teacher - NCLB Highly Qualified
f(x) = x^3 - x
f'(x) = 3x^2 - 1
f'(-1) = 3(-1)^2 - 1
f'(-1) = 2
(y - 1) = 2(x + 1)
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