Doug C. answered 10/15/18
Math Tutor with Reputation to make difficult concepts understandable
Hi Zac,
This is a challenging problem. There might be an easier technique, but I just took the first strategy that came to mind. I used (a, f(a)) as the point on the curve for which to generate the equation of the tangent line (where f(x) is the function defined by the ellipse in the first quadrant). Once you have the equation of the tangent line, find the x and y intercepts. Then you can create a function that gives the area of the triangle. Finally find the derivative of that function, set equal to zero, and locate the critical points.
This graph has many of the details (but not all of them).
https://www.desmos.com/calculator/zhlpxyf572
Hopefully this answer will be published by WyzAnt--there have been some issues (at least for me) when including links to Desmos URLs in responses.