
Andy C. answered 10/10/18
Tutor
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Math/Physics Tutor
Revenue function R(x) = x*p = x(200-4x) = 200x - 4x^2
0 = dR/dx = 200 - 8x
200 = 8x
x=25
Alissa G.
asked 10/10/18A demand function p=200-4x, where p is the price per unit and x is the number of units produced and sold (the demand). Find x for which the revenue is maximum.
Andy C. answered 10/10/18
Math/Physics Tutor
Revenue function R(x) = x*p = x(200-4x) = 200x - 4x^2
0 = dR/dx = 200 - 8x
200 = 8x
x=25
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