Russ P. answered 10/13/14
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Sam,
Since the corrals are adjacent they share one wall,
Let a = length of shared wall. There are 3 of those if both corrals have the same length in one direction
Let b = length of corral 1 in other direction of the rectangle
Let c = length of corral 2 in other direction of the rectangle, in general b & c are NOT equal
Let P = the length of the fencing needed (given as 240 ft) which includes the shared wall a
Let A = summed area of both rectangles = 2000 sq. ft since each is 1000 sq. ft.
Then,
P = 3a + 2(b + c) = 240
A = a(b + c) = 2000 , solving for (b + c) = 2000/a because a is non-zero
P = 3a + 2(2000/a) = 240, or multiplying both sides by a
3a2 + 4000 = 240a , or 3a2 -240a + 4000 = 0 or a2 -80a + 4000/3 =0. Now let's complete the square
(a - 40)2 + (1333.33 - 1600) = 0 since we added 1600 to complete the square, we must also subtract it to maintain the original equality.
Simplifying: (a - 40)2 = 266.667
Solving by taking square roots of both sides: (a-40) = +- 16.333 or a = 56.333 ft. and a = 23.667 ft.
And (b + c) = 2000/a = 2000/56.333 = 35.50 ft and 2000/23.667 = 84.51 ft. depending on a
And since each corral has an area of 1000 sq. ft., then ab = 1000 and ac = 1000 so you can also solve for b & c separately for each solution for a:
So b = 1000/56.333 = 17.75 ft = c;
Or b = 1000/23.667 = 42.25 ft. = c
Check:
P = 3(56.333) + 2(35.50) = 169.0 + 71.0 = 240.0 ft. for this solution pair: a = 56.333 & (b + c) = 35.50 ft
P = 3(23.667) + 2(84.51) = 71.0 + 169.0 = 240.0 ft. for the second solution pair: a = 23.667 & (b + c) = 84.51 ft.