Chontra,
I don't use drugs so I can't use the addiction method to solve these equations :)
But I can use the addition method;
Essentially, you rearrange, align and multiple one or both equations by constants so that one of the variables drops out when the two equations are added because the terms are identical with opposite signs.
6x + y = -5 Multiply left and right sides by 2 to get +2y because there is a -2y in the second equation.
Thus 12x + 2y = -10 is now the first equation set up
4x - 2y = -86 is the original second equation. Just add them on both sides of the = sign
16x + 0 = -96 so x = -96/16 = - 6, Now substitute this value for x in any equation and solve for y
6(-6) + y = -5 so y = -5 + 36 = 31 in the first equation.
So the solution to this pair of equations is x = -6 and y = 31.
Note, if the original two equation were such that one was a constant multiple of the other, they would not be independent, and no solution would be possible because both the x and the y terms would drop out during the addition. Try it solving the pair: 6x + y = -10 and 60x +10y = -100 which are not independent equations.
