
Philip P. answered 10/01/14
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Let h = the height of the box and a = the length of a side on the top & bottom. The volume of the box is:
Volume = 1216 ft3 = a2h, so h = 1216/a2
The surface area of the top and bottom is a2. The surface area of the lateral sides is 4ah.
Cost = Cost of top + Cost of bottom + Cost of sides
Cost = ($0.10)a2 + ($0.20)a2 + ($0.025)(4ah)
Substitute h=1216/a2:
Cost = (0.3)a2 + (0.025)(4*a*1216/a2)
Cost = (0.3)a2 + (121.6)/a
To find the minimum cost, take the first derivative of Cost wrt a, set it to zero, and solve for a:
d(cost)/da = (0.6)a - 121.6/a2
0 = (0.6)a - 121.6/a2
121.6/a2 = (0.6)a
121.6/(0.6) = a3
(202.67)1/3 = a
5.87 ≅ a
h = 1216/a2 = 1216/(5.87)2 = 35.29