vertex form of 7x^2 − 14x + 1

Question

find standard form 

Answer 1

y = 7x² - 14x + 1

 

   = 7(x² - 2x) + 1 = 7(x² - 2x + 1 - 1) + 1

 

                            = 7(x-1)² - 7 + 1

 

y = 7(x-1)² - 6   vertex = (1, -6)

 

Answer 2

Complete the square:

 

7(x² -2x +1) + 1 -7

 

7(x-1)² -6

 

Vertex is (1, -6)