Write an equation in slope-intercept form for the line that satisfies the following condition. passes through (11, –15) and (16, 5)

Question

answer pleaseim trying to passs 

Answer 1

Hello, Danielle,

The first thing that you must do is find the slope of the line.  Remember that you can call either point as (x1,y1) or (x2,y2).  Another thing that you must be careful with is that the formula for the slope is

 

m= (y2-y1)/ (x2-x1)        The y's in the numerator and the x's on the bottom.  This is a common mistake that my

                                      students make. 

 

OK.  I am going to call (11, -15), (x1,y1) and (16, 5), (x2,y2).  I am going to proceed plugging the values for x1=11, x2=16, y1= -15, and y2=5 into the above formula

 

m= [5-(-15)]/ [16-11]= 20/5=4      So, m=4. 

 

Next, I am going to use The Point-Slope Form

 

y-y1 = m( x-x1).  Note that one of the y and one of the x do not have a subscript. (a number next to it).  I am going to plug in the values for x1=11 and y1= -15 into the above formula. Remember m, the slope, is 4.

 

y-(-15)= 4(x-11) 

y+15= 4x-44             Using the Distributive Property.  Also note that -(-15) becomes +15

   -15       -15             Subtracting 15 from both sides.

y      = 4x-59             Subtracting 4x from both sides. 

So, the equation in the Slope-Intercept Form is y= 4x-59

 

Hey, keep trying math gets easier with practice.  Good luck, thanks for posting.

D. Y. Taylor

Don't forget to rate me.

 

 

Answer 2

let x₁ = 11, y₁= -15, x₂ = 16, and y₂ = 5

 

Use the two-point form for the equation of a line, which is

y - y₁  = y₂ - y₁

x - x₁     x₂ - x₁

 

y - (-15) = 5 - (-15)

x - 11        16 - 11

 

y + 15 = 20 = 4     Since this is a proportion, you should cross multiply

x - 11     5

 

y + 15 = 4x -44

y = 4x - 59