ANdrew .
asked 09/05/18Determine ƒ(–a) where ƒ(x) = x2– 6x and simplify.
A ƒ(–a) = –a2 + 6a
B ƒ(–a) = a2 – 6a
C ƒ(–a) = a2 + 6a
D ƒ(–a) = –a2 – 6a
B ƒ(–a) = a2 – 6a
C ƒ(–a) = a2 + 6a
D ƒ(–a) = –a2 – 6a
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1 Expert Answer

Mark M. answered 09/05/18
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
f(x) = x2 - 6x
f(-a) = (-a)2 - 6(-a)
Now simplify and answer.
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Deysi D.
what is the answer01/18/21