V(x)= 6x^3+9x^2-24x+36 , where x is the widthof the room in meters. If the volume is 45 cubic meters , what is the width of the room ?

Question

The volume of a computer room in Zeki's, an internet cafe is expressed in the pynomial function V(x)= 6x^3+9x^2-24x+36 , where x is the widthof the room in meters. If the volume is 45 cubic meters , what is the width of the room ?

Answer 1

if V(x) = 6x³+9x²-24x+36 = 45 meters³

then

V(x) = 6x³+9x²-24x-9=0

Plugging this into a cubic solver, we find that x = width = 1.596, -2.754, & -.3412

The only reasonable answer then is width = 1.596 meters