This is a brute force question.
Use a spreadsheet like Excel and simply plug the required values into the spreadsheet.
However, what is being demonstrated here is that even though the function is undefined (0/0) and discontinuous at x = 2, it, in fact, has a so-called removable discontinuity at x = 2 and a limit of 1/2 at x = 2. To see this factor the numerator and denominator and divide out the common factor.
It also has another essential discontinuity and vertical asymptote at x = -2.