Inactive Tutor answered 08/24/18
Tutor
New to Wyzant
(sinx)(tanx cosx-cotx cosx)=
=sinxcosx(sinx/cosx-cosx/sinx)=
=sinxcosx((sin2x-cos2x)/(sinxcosx))=sin2x-cos2x
= 1-cos2x-cos2x=1-2cos2x
Athena V.
asked 08/24/18Inactive Tutor answered 08/24/18
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.