Neutralization

Question

What volume (in ml) of 0.395 mol/L Calcium Hydroxide, ca(OH)2(aq) is needed to completely netralize 22.8 ml of 0.343mol/L phosphoric acid, H3PO4(aq)?

 

3CA(OH)2 + 2H3PO4 = Ca3(PO4)2 + 6H20

Answer 1

 

 

conc x vol = conc x vol

 

so, 22.8 mL x 0.343 mol/1000mL x 3 H+/H3PO4 = x mL  Calcium Hydroxide, ca(OH)2 x 0.395 mol/1000mL Calcium Hydroxide, ca(OH)2 x 2 OH-/Ca(OH)2

 

23.46 = .79(x mL Ca(OH)2

 

x mL Ca(OH)2 = 29.7 mL