What volume of oxygen gas at STP is required to react with 10g of potassium metal according to the following equation?

Question

2K(s)+O2(g) = K2O(s)

 

a) 5.8 L

b) 8.7 L

c) 1.5 L

d) 11.5 L 

e) 2.9 L

 

My predication is b) I'm unsure 

Answer 1

What volume of oxygen gas at STP is required to react with 10g of potassium metal according to the following equation?

 

2K(s)+O2(g) = K2O(s)

 

10 g K x 1 mole K/39.10 g K x 1 mole O2/ 2 mol K x 22.4 L/1mole + ?

 

2.86 L