Tricky fraction question! Please help!

Question

A flock of geese on a pond were being observed continuously. At 1pm, 1/5 of the geese flew away. At 2pm, 1/8 of the geese that remained flew away. At 3pm, three times as many geese as had flown away at 1pm, flew away, leaving 32 geese on the pond. At no other time did any geese arrive, fly away, or die. How many geese were in the original flock?

Answer 1

Let's start with the original amount, x.

After the first loss, we are left with (4/5)x

After the second loss, we are left with 7/8 of what we had: (7/8)((4/5)x)

Then the time the first loss flew away: so we subtract 3(1/5)x: (7/8)((4/5)x) - (3/5)x which now equals 32

So:

((28/40)-(3/5))x= 32

So (4/40)x = 32

X= 320