
Robert Z. answered 08/01/18
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Let F be the 1st number, S the 2nd.
First condition: F = S - 5
Second condition: 3F = 6S + 6
Substituting for F: 3(S - 5)= 6S + 6
Expanding: 3S - 15 = 6S + 6
Solving: 3S - 6S = 6 + 15
-3S =21