Mark M. answered 07/22/18
Tutor
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(954)
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Let y = (1.646)t
Then lny = ln[(1.646)t
= tln(1.646)
So, y'/y = ln(1.646)
y' = ln(1.646)y = ln(1.646)(1.646)t
So, if A = 508(1.646)t, then dA/dt = 508ln(1.646)(1.646)t
≈ 253.16(1.646)t