find the value of y so that the line passing through the points (2,5) and (7,Y) has a slope of 2/3

Question

 (2,5) and (7,y) has a slope of 2/3 

Answer 1

slope is found by:  m = (y₂-y₁)/(x₂-x₁)

 

(x₁,y₁) = (2,5) and (x₂,y₂) = (7,y)

 

(y-5)/(7-2) = 2/3

 

(y-5)/5= 2/3

cross multiply

3(y-5) = 5(2)

3y - 15 = 10

3y = 25

y = 25/3

Answer 2

y-y1=m(x-x1)

5-Y=2/3(2-7)

5-Y=2/3(-5)

5-Y=-10/3

15-3Y=-10

25=3Y

Y=25/3= 8 1/3