6x^2 + 4x - 5 = 0 in quadratics formula

Question

i'm having trouble with this in my math class

Answer 1

If you want to solve it using the quadratic formula, do the following:

x = -b ± √(b² - 4ac)          a = 6, b = 4, c = -5

              2a

 

x = -4 ± √[4² - 4(6)(-5)]

               2(6)

 

x = -4 ± √(16 + 120)

               12

 

x = -4 ± √136

            12

 

x = -4 ± √4√34 

           12

 

x = -4 ± 2√34 

            12

 

x = -2 ± √34

            6

 

 

Answer 2

Nevermind, I got it.

 

ax² + bx + c

 

x = (-b ± √(b² - 4ac))/2a

x = (-4 ±√(4² - 4(6)(-5)))

x = -4 ± √(16 + 120))

x = -4 ± √136

x = -4 ± 2√34

 

I dunno if you need to go further, but I will just in case.

 

x = -4 + 2√34

 

x = -4 - 2√34

 

Throw each right side in your calculator for your answers.