
Arturo O. answered 05/12/18
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t = time going out at 20 mph ⇒ outward travel distance is 20t
4 - t = time coming back at 30 mph ⇒ return travel distance is 30(4 - t)
The 2 distances must be the same, so
20t = 30(4 - t)
50t = 120
t = 120/50 hours = 2.4 hours
The maximum distance from dock is
20t = (20 miles/hour)(2.4 hours) = 48 miles