using reference angle find the exact value

Question

tan(sin^-1(x+1⁄2))

Answer 1

tan(a)=sin(a)/cos(a)=sin(a)/√(1-sin²(a))

Since sin(sin^-1(a))=a, therefore

tan(sin^-1(x+1/2))=sin(sin^-1(x+1/2))/√(1-sin²(sin^-1(x+1/2)

=(x+1/2)/√(1-(x+1/2)²)=(2x+1)/√(4-(2x+1)²)