
Bobosharif S. answered 04/29/18
Tutor
4.4
(32)
PhD in Math, MS's in Calulus
Horizontal tangent is the point, where f'(x)=0 and tangent is parallel to x-axis. The first derivative is 3x2-16x+5.
Solving equation
3x2-16x+5=0,you get x=1/3 and x=5, which are the x-coordinates of the tangent point(s). Now we can find y-coordinates.
For x=1/3, f(1/3)=3.81481
For x=5, f(5)=-47
So, coordiantes are (1/3, 3.81) and (5, -47).
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