Let A(1,3), B (-2,-4) and C(1,-2) be a triangle. Find the equation of the perpendiculars from the vertices to the opposite sides

Question

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Answer 1

Side AB is opposite vertex C.

 

Slope AB = (-4-3) / (-2-1) = 7/3

 

Slope of perpendicular to AB = -3/7

 

Perpendicular line to AB that contains vertex C has equation: 

 

    y - (-2) = (-3/7)(x-1)

 

            y = (-3/7)x - (11/7)

 

Follow a similar procedure for the other two lines.